The length of a rectangle is twice the width. The perimeter is 25. The system to help find the length and width is:
L=2W

2L+2W=25

Aaron tried using a graph to find the measurements but was unsure of the exact values. Use substitution to solve the system exactly. Round to the nearest hundreth.

Let the width be x
Since the question mentions the length is twice the width,
let the length be 2x
The total perimeter given is 25cm and as we know, perimeter for a rectangle :
=> P = 2(Length + width)
So,

25cm = 2(2x + x)
25 = 4x + 2x
25 = 6x
25/6 = x
4.166666667 = x

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The length of a rectangle is twice the width. The perimeter is 25. The system to help find the length and width is: L=2W 2L+2W=25 Aaron tried using a graph to find the measurements but was unsure of the exact values. Use substitution to solve the system exactly. Round to the nearest hundreth.

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The length of a rectangle is twice the width. The perimeter is 25. The system to help find the length and width is:
L=2W

2L+2W=25

Aaron tried using a graph to find the measurements but was unsure of the exact values. Use substitution to solve the system exactly. Round to the nearest hundreth.