Given :
A car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105 m.
To Find :
The acceleration of the car.
Solution :
We know, by equation of motion :
[tex]2as = v^2 -u^2\\\\a = \dfrac{v^2 -u^2 }{2s}\\\\a = \dfrac{(-10.9)^2 - ( -27.7)^2}{2\times ( -105 )}\\\\a = 3.088\ m/s^2[/tex]
Therefore, acceleration of the car is 3.088 m/s².
