Answer:
moles of Ba²⁺ : 0.97 mol
Moles of OH⁻ : 1.94 mol
Explanation:
Given data:
Mass of Ba(OH)₂ = 165.5 g
Moles of barium ions = ?
Moles of hydroxide ion = ?
Solution:
Number of moles of barium hydroxide:
Number of moles = mass/molar mass
Number of moles = 165.5 g/ 171.34 g/mol
Number of moles = 0.97 mol
one mole of barium hydroxide contain one mole of Ba²⁺ and 2 mole of OH⁻ ion.
Thus in 0.97 moles of barium hydroxide,
moles of Ba²⁺ :
0.97 mol × 1 = 0.97 mol
Moles of OH⁻ :
0.97 mol × 2= 1.94 mol
