Answer:
F = 159.07 N
Explanation:
Given that,
Mass of a tennis ball, m = 54.9 g = 0.0549 kg
It accelerates from rest to a speed of 45.1 m/s.
The impact with the racket gives the ball a constant acceleration over a distance of 35.1 cm = 0.351 m
We need to find the magnitude of net force acting on the ball.
Let a be the acceleration of the ball. Using third equation of motion to find it.
[tex]v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(45.1)^2-(0)^2}{2\times 0.351}\\\\=2897.45\ m/s^2[/tex]
Net force,
F = ma
F = 0.0549 kg × 2897.45 m/s²
= 159.07 N
Hence, the net force acting on the ball is 159.07 N.
