Answer:
The speed of the box at the end of the 6 s interval is 7.5 m/s.
Explanation:
Given;
magnitude of the force, f = 15 N
mass of the box, m = 12 kg
initial velocity of the box, u = 0
time of the box motion, t = 6s
The applied force on the box is given by Newton's second law of motion;
f = ma
where;
a is the acceleration of the box
a = f / m
a = (15) / (12)
a = 1.25 m/s²
The final velocity of the box is calculated as;
v = u + at
v = 0 + (1.25 x 6)
v = 7.5 m/s.
Therefore, the speed of the box at the end of the 6 s interval is 7.5 m/s.
