Answer: the value of the required thickness is 41.4 cm
Explanation:
Given that;
R1 = 17
R2 = 44
L1 = 16
L2 = ?
we know that, from thermal conductivity formula
P = 1 / R
P = k / L
1 / R = k / L
since k of a distinct material is constant,
we can take
L / R = constant
L1 / R1 = L2 / R2
L1R2 = L2R1
L2 = (L1 × R2) / R1
so we substitute
L2 = (16 × 44) / 17
L2 = 704 / 17
L2 = 41.4 cm
Therefore the value of the required thickness is 41.4 cm