Answer: the acceleration is 1.282 m/s²
Explanation:
Given that;
Time t = 13 sec
Initial velocity U = 5 kmph = (5 × 1000)/(60 × 60) = 1.3888 m/s
final velocity V = 65 kmph = (65 × 1000)/(60 × 60) = 18.0555 m/s
Now we know that;
V = U + at
we substitute
18.0555 = 1.3888 + 13a
18.0555 - 1.3888 = 13a
13a = 16.6667
a = 16.6667 / 13
a = 1.282 m/s²
Therefore the acceleration is 1.282 m/s²