Answer:
The coordinates of B is (-8,-5).
Step-by-step explanation:
The midpoint of line AB is M. The coordinate of M is (-6,-4).
The coordinates of A is (-4,-3)
We need to find the mid point of B.
If M(x,y) is the midpoint of the coordinates (x₁,y₁) and (x₂,y₂). The mid point theorem is used as follows :
[tex]M(x,y)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})[/tex]
Let the mid point of B is (x₂,y₂). Put (x,y) = (-6,-4), (x₁,y₁) = (-4,-3).
[tex](-6,-4)=(\dfrac{-4+x_2}{2},\dfrac{-3+y_2}{2})\\\\\dfrac{-4+x_2}{2}=-6\ \text{and}\ \dfrac{-3+y_2}{2}=-4\\\\-4+x_2=-12\ \text{and}\ -3+y_2=-8\\\\x_2=-12+4\ \text{and}\ y_2=-8+3\\\\x_2=-8\ \text{and}\ y_2=-5[/tex]
So, the coordinates of B is (-8,-5).
The coordinates of B are (-8, -5).
Given that,
The midpoint of AB is M(-6, -4). If the coordinates of A is (4,-2),
We have to determine,
The coordinates of B.
According to the question,
The midpoint of line AB is M. The coordinate of M is (-6,-4).
And the coordinates of A is (-4,-3)
If M(x, y) is the midpoint of the coordinates (x₁, y₁) and (x₂, y₂). The midpoint theorem is used as follows :
[tex]M(x, y) = ( \dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2})[/tex]
Let the midpoint of B be (x₂, y₂).
M (x, y) = (-6,-4), and (x₁, y₁) = (-4,-3).
[tex]M(-6, -4) = ( \dfrac{-4+x_2}{2}, \dfrac{-3+y_2}{2})\\\\[/tex]
Solving the equation for the co-ordinate B.
[tex]\dfrac{-4+x_2}{2} = -6\\\\-4 + x_2 = -6 \times 2\\\\-4 + x_2 = -12\\\\x_2 = -12+4\\\\x_2 = -8[/tex]
And,
[tex]\dfrac{-3+y_2}{2} = -4\\\\-3 + y_2 = -4 \times 2\\\\-3 + y_2 = -8\\\\y_2 = -8 + 3\\\\y_2 = -5[/tex]
Hence, The required coordinates of B are (-8, -5).
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