A. 207 kJ
B. 4730 kJ
C. 9460 kJ
D. 414 kJ

Answer:
Q = 9460 Kj
Explanation:
Given data:
Mass of copper = 2kg
Latent heat of vaporization = 4730 Kj/Kg
Energy required to vaporize 2kg copper = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram copper is 4730 Kj thus, for 2 kg
by putting values,
Q= 2kg × 4730 Kj/Kg
Q = 9460 Kj