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#1) Line j contains points (-3,5) and (6,-1). If line p is PERPENDICULAR to linej,
what is the slope of line p? (Must reduce fraction) *
-3/2
3/2
9/4
- 2/3

Respuesta :

meowmeow223334
First find slope of line j
(-1-5)/(6+3) = -6/9 = -2/3
Perpendicular = opposite sign and reciprocal slope

Solution: 3/2

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