Answer:
For the value of hypotenuse can be irrational, sum of squares of other two legs might be imperfect square number.
Step-by-step explanation:
We all know, the Pythagorean theorem can be stated as follows:
The sum of squares of two legs of a right angled triangle is equal to the square of the hypotenuse.
i.e.
[tex]a^2+b^2=c^2[/tex]
Where, [tex]c[/tex] is the hypotenuse and [tex]a, b[/tex] are the two other legs of the right angled triangle.
Given that:
[tex]a[/tex] and [tex]b[/tex] are rational numbers.
To find:
Situation for which [tex]c[/tex] is irrational.
Square of a rational number is always rational.
So, [tex]a^{2} , b^{2}[/tex] both will be rational.
And sum of squares of two rational numbers will also be rational.
Therefore, [tex]a^2+b^2[/tex] will also be rational.
and
[tex]c = \sqrt{a^2+b^2}[/tex]
For the value of [tex]c[/tex] can be irrational, sum of squares of other two legs might be imperfect square number.
