Answer:
m= -2 1/2
Step-by-step explanation:
First, let's put the equation into slope intercept form.
6x-15y=270
-15y=-6x+270
y=6/15x+270
For two lines to be perpendicular, their slopes must be opposite reciprocals.
m=-15/6 or m= -2 1/2
Answer:
slope = - [tex]\frac{5}{2}[/tex]
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
6x - 15y = 270 ( subtract 6x from both sides )
- 15y = - 6x + 270 ( divide all terms by - 15 )
y = [tex]\frac{-6}{-15}[/tex] x - 18, that is
y = [tex]\frac{2}{5}[/tex] x - 18 ← in slope- intercept form
with slope m = [tex]\frac{2}{5}[/tex]
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{2}{5} }[/tex] = - [tex]\frac{5}{2}[/tex]
