Answer:
3-bromo-4-ethyl-2,2,5-trimethyloctane.
Explanation:
You need to find the longest carbon chain. In this molecule, the longest carbon chain goes straight across and contains 8 carbons (oct-). There are no double or triple bonds so its octane.
Number the carbon chain from 1-8, starting at the end that is closest to a group. The left side is closest to a group so start from there.
On carbon 2, there are two methyl groups. On carbon 5, there is one methyl group. When naming, it will be 2,2,5-trimethyl.
On carbon 3, there is one bromine group. When naming, it will be 3-bromo.
On carbon 4, there is one ethyl group. When naming, it will be 4-ethyl.
Order the names of the groups alphabetically in front of octane.
The name of the compound is 3-bromo-4-ethyl-2,2,5-trimethyloctane.
