Answer:
a. The rock takes 2.02 seconds to hit the ground
b. The rock lands at 20,2 m from the base of the cliff
Explanation:
Horizontal motion occurs when an object is thrown horizontally with an initial speed v from a height h above the ground. When it happens, the object moves through a curved path determined by gravity until it hits the ground.
The time taken by the object to hit the ground is calculated by:
[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]
The range is defined as the maximum horizontal distance traveled by the object and it can be calculated as follows:
[tex]\displaystyle d=v.t[/tex]
The man is standing on the edge of the h=20 m cliff and throws a rock with a horizontal speed of v=10 m/s.
a,
The time taken by the rock to reach the ground is:
[tex]\displaystyle t=\sqrt{\frac{2*20}{9.8}}[/tex]
[tex]\displaystyle t=\sqrt{4.0816}[/tex]
t = 2.02 s
The rock takes 2.02 seconds to hit the ground
b.
The range is calculated now:
[tex]\displaystyle d=10\cdot 2.02[/tex]
d = 20.2 m
The rock lands at 20,2 m from the base of the cliff
