Answer:
a. t = 2.02 s
b. d = 20.2 m
Explanation:
Horizontal Motion
If an object is thrown horizontally from a height h with a speed v, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
The time the object takes to hit the ground can be calculated as follows:
[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]
The time does not depend on the initial speed.
The range or maximum horizontal distance traveled by the object can be calculated by the equation:
[tex]\displaystyle d=v.t[/tex]
The man standing on the edge of the h=20 m cliff throws a rock with an initial horizontal speed of v=10 m/s.
a.
The time taken by the rock to reach the ground is:
[tex]\displaystyle t=\sqrt{\frac{2*20}{9.8}}[/tex]
[tex]\displaystyle t=\sqrt{4.0816}[/tex]
t = 2.02 s
b.
The range is:
[tex]\displaystyle d=10\cdot 2.02[/tex]
d = 20.2 m
