a guitar string is 0.620 m long, and oscillates at 234 Hz. if a player uses his finger to shorten the string to 0.480 m, what is the new frequency?

Respuesta :

solve the x u will get 181.16
Ver imagen hazrey

Answer:

the new frequency is : 302.25Hz

using the formula F2 = [tex]\frac{F1 L1}{L2}[/tex]

Explanation:

meaning of frequency

frequency of a string is the number of vibrations of a plucked string per second. it is measured in Hertz.

the frequency of a string is inversely proportional to twice the length of the string. which means the longer the string, the smaller the freqency and the higher the string the higher the frequency.

f ∝ 1/2L.

f = k/2L

where f = frequency

                         L = length of string

                         k = constant

k = 2fL is a constant

given data

L1 = 0.62m

f1 = 234Hz

L2 = 0.48m

2f1L1 = 2f2L2

f1L1 = f2L2

f2 = f1L1/L2

f2 = [tex]\frac{234 x 0.62}{0.48}[/tex] = 302.25Hz

in conclusion, the new frequency is 302.25Hz

learn more about frequency of a vibrating string: brainly.in/question/1149252

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