Given:
[tex]\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}[/tex]
To prove:
[tex]\Delta CDA\cong \Delta ABC[/tex]
Proof:
In [tex]\Delta CDA\text{ and } \Delta ABC[/tex],
[tex]\overline{AB}\cong \overline {CD}[/tex] because Given
[tex]\overline{BC}\cong \overline {DA}[/tex] because Given
[tex]\overline{AC}\cong \overline {AC}[/tex] because Reflexive property.
Corresponding sides of both triangles are congruent. So,
[tex]\Delta CDA\cong \Delta ABC[/tex] because SSS
Therefore, the required missing values are: Given, [tex]\overline{BC}\cong \overline {DA}[/tex], Reflexive property ,[tex]\Delta CDA\cong \Delta ABC[/tex], SSS respectively.
