Respuesta :
Answer:
E₀ = 5.97 10⁸ N / C
Explanation:
Coulomb's law in a material medium is written
[tex]F = \frac{1}{4\pi \epsilon } \frac{q_{1} q_{2} }{r^{2} }[/tex]
ε is the electrical permittivity of the material
Electric field and force are related
F = q E
in dielectric materials such as mica there is an electric field inside the material that decreases the external field
E = E₀ /ε
where ε is the electrical permittivity of the material; in general it is tabulated in the form
[tex]\epsilon _{r} =\frac{\epsilon}{\epsilon_{o}}[/tex]
[tex]\epsilon = \epsilon_{r} \ \epsilon_{o}[/tex]
we substitute
F = q E₀ / \epsilon_{r} \epsilon_{o}
[tex]E_{o} = \frac{F \ \epsilon_{r} \ \epsilon_{o} }{q}[/tex]
for the case of mica it is equal to er = 5.4 and suppose a test charge equal to the charge of the electron
we calculate
E₀ = 2 5.4 8.85 10⁻¹² / 1.6 10⁻¹⁹
E₀ = 59.74 10⁷
E₀ = 5.97 10⁸ N / C
