Answer: Our inequality is given by
[tex]6x-4\frac{9}{10}<18\frac{1}{8}[/tex]
Step-by-step explanation:
Since we have given that
Four and nine tenths less than the product of a number and six is no more than eighteen and one-eighth.
Let the number be 'x'.
So, it becomes,
[tex]6\times x-4\frac{9}{10}<18\frac{1}{8}\\\\6x-\frac{49}{10}<\frac{145}{8}\\\\6x<\frac{145}{8}+\frac{49}{10}\\\\6x<\frac{145\times 5+49\times 4}{40}\\\\6x<\frac{725+196}{40}\\\\6x<\frac{921}{40}\\\\x<\frac{921}{6\times 40}\\\\x<\frac{921}{240}[/tex]
Hence, our inequality is given by
[tex]6x-4\frac{9}{10}<18\frac{1}{8}[/tex]
