Earl has deposited $798 in a savings account that earns interest at a rate of 3.1% compounded quarterly. What will the account balance be in 21 years?

Respuesta :

[tex]A=P(1+ \frac{r}{n} )^{rt}[/tex]

A=future amount
P=present amount
r=rate in percent
n=number of times per year it is compounded
t=time in years


given
P=798
r=0.031
n=4
t=21

[tex]A=798(1+ \frac{0.031}{4} )^{(4)(21)}[/tex]
[tex]A=798(1+ 0.00775 )^{84)}[/tex]
[tex]A=798(1.00775 )^{84)}[/tex]
A=1526.2956
A=1526.30

about $1526.30

Answer:

the answer is d

Step-by-step explanation: