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NobleAlexander
7^2 

Our Factor is: 7
Our Power is: 2

The power determines the number of times it will multiply by that factor.
So in this case: 
7^2 = 7 * 7 = 49

2^8 

Our Factor is:  2
Our Power is: 8

So we need to multiply the factor by itself 8 times. (Think of it as 2 needs to show up 8 times... so if you were to count the number of 2's you'd see there are 8!) 

2*2*2*2*2*2*2*2 = (2*2)(2*2)(2*2)(2*2) = 4*4*4*4 = (4*4)(4*4) = 16*16 = (16*16) = 256

Or if you want to think of it differently you can do the problem like this: 
2^8

2*2 = 4
4*2 = 8
8*2 = 16
16*2 = 32
32*2 = 64
64*2 = 128
128*2 = 256

You should see 7, *2's. (It will always be one less than the power)  

5^5

Our Factor is: 5
Our Power is: 5

5^5 = 5*5*5*5*5 = (5*5)(5*5)*5 = 25*25*5 = (25*5)*25 = 125*25 = 3125

Or you could think of it like this: 
5*5 = 25
25*5 = 125
125*5 = 625
625*5 = 3125

7²  =  7  x  7   =   49

2⁸  =  2 x 2 x 2 x 2 x 2 x 2 x 2 x 2  = 256

5⁵  = 5  x  5 x  5  x 5  x 5  =  3125

Consider a power of the form [tex]a^b[/tex] , a represents the base while b is the exponent. To write the power as a product of the same factor, it means a must be multiplied by itself in b places

Applying this rule of powers to the given question, the powers as a product of the same factor are given below.

7²  =  7  x  7   =   49

2⁸  =  2 x 2 x 2 x 2 x 2 x 2 x 2 x 2  = 256

5⁵  = 5  x  5 x  5  x 5  x 5  =  3125

Learn more here: https://brainly.com/question/8268119

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