Mei has 8 jars of soup. Each jar contains 300 millimeters of soup. What is the smallest pot mei can use to heat all the soup.

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Answer:

Pan of 2.4 liters can be used.

Step-by-step explanation:

Since Mei has 8 jars of soup and each jar contains 100 milliliters of soup.

We have to calculate the smallest pot Mei can use to heat all the soup.

Total volume of soup = Number of jars × Volume of one jar (Volume of soup in one jar) = 8×300 = 2400 ml.

∵ 1000 ml is equal  to 1 liters

∴ 1 ml is equal to 1/1000 liters

∴ 2400 ml soup is = 2400×(1/1000) = 2.4 liters

So a pan with volume of 2.4 liters can be used.

Answer:

3 liters

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