if a+bi is a root, then a-bi is also a root
5+4i is a root, 5-4i is also a root
if f(0)=287
For f(0)=287, therefor it is
f(x)=sometingx+287 since the x's cancel for f(0)
5-4i and 5+4i
(x-(5-4i)) and (x-(5+4i))
(x-5+4i)(x-5-4i)
x^2-10x+41
right now, f(x)=41
41*what=287
Divide both sides by 41
what=7
time whole equation by that
f(x)=7(x^2-10x+41)
f(x)=7x^2-70x+287
