Respuesta :
use conservation of momentum
m1v1 + m2v2 = (m1 + m2)v3
50 x 10 + 0 = (50+m) x 2.5
500 = 125 + 2.5m
2.5m = 375
m = 150kg
m1v1 + m2v2 = (m1 + m2)v3
50 x 10 + 0 = (50+m) x 2.5
500 = 125 + 2.5m
2.5m = 375
m = 150kg
Answer:
Mass of the cart is 150 kg.
Step-by-step explanation:
Mass of the boy = 50 kg
Speed of the boy = 10 meter per second
Momentum of the boy = mv
Where m = mass of the boy
v = velocity of the boy
Momentum of the boy = 50 × 10 = 500 kg meter per second
Let the mass of the cart = m
Therefore, mass of the cart with the boy = (m + 50) Kg
Velocity of the cart after the boy jumps on it = 2.5 meter per second.
Momentum of the cart with boy = (m + 50)2.5
Now by conservation of the momentum,
(m + 50)2.5 = 500
m + 50 = [tex]\frac{500}{2.5}[/tex]
m + 50 = 200
m = 200 - 50
m = 150 kg
Therefore, mass of the cart is 150 kg.