we have
[tex] 2x-2y=6 [/tex] ------> equation [tex] 1 [/tex]
[tex] 4x+4y=28 [/tex] ------> equation [tex] 2 [/tex]
Multiply by [tex] 2 [/tex] the equation [tex] 1 [/tex]
[tex] 4x-4y=12 [/tex] ------> equation [tex] 3 [/tex]
Sum equation [tex] 2 [/tex] and equation [tex] 3 [/tex]
[tex] 4x+4y=28\\ 4x-4y=12\\ ------\\ 8x=40\\ x=40/8\\ x=5 [/tex]
Substitute the value of x in the equation [tex] 2 [/tex]
[tex] 4x+4y=28 [/tex]
[tex] 4*5+4y=28\\ 4y=28-20\\ 4y=8\\ y=8/4\\y=2 [/tex]
therefore
the answer is the option B
[tex] (5,2) [/tex]