Answer : The mass of the 3.7 mole of [tex]PbO_2[/tex] is, 885.04 grams
Solution : Given,
Moles of [tex]PbO_2[/tex] = 3.7 moles
Molar mass of [tex]PbO_2[/tex] = 239.2 g/mole
Formula used :
[tex]\text{Mass of }PbO_2=\text{Moles of }PbO_2\times \text{Molar mass of }PbO_2[/tex]
Now put all the given values in this formula, we get the mass of [tex]PbO_2[/tex]
[tex]\text{Mass of }PbO_2=(3.7moles)\times (239.2g/mole)=885.04g[/tex]
Therefore, the mass of the 3.7 mole of [tex]PbO_2[/tex] is, 885.04 grams
