Respuesta :
You have to find the greatest common factor GCF for each number, you can do it for both at the same time:
foot ---- hand
GCF 48 60
2 24 30
2 12 15
3 4 5
From here you dont have more numbers (GCF) for this pair, now for finding the greatest number of identical kits multiply the GCFs: 2*2*3=12 you have 12 kits containing 4 foot-warmer packets and 5 hand-warmer packets (from table the last row in foot and hand)
foot ---- hand
GCF 48 60
2 24 30
2 12 15
3 4 5
From here you dont have more numbers (GCF) for this pair, now for finding the greatest number of identical kits multiply the GCFs: 2*2*3=12 you have 12 kits containing 4 foot-warmer packets and 5 hand-warmer packets (from table the last row in foot and hand)
The greatest number of identical kits they can prepare using all of the hand warmer and foot warmer packets is 12.
The number of head-warmers in each kit is 5.
The number of foot-warmers in each kit is 4.
In order to determine the greatest number of identical kits that can be prepared using all of hand warmer and foot warmer packets can be determined by determining the highest common factor of 60 and 48.
Factors of 60 = 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30 and 60.
Factors of 48 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
Common factors = 1, 2, 3 ,4,12
The highest common factor = 12
Number of hand-warmers in the kit = 60 / 12 = 5
Number of foot-warmers in the kit = 48 / 12 = 4
To learn more about highest common factor, please check: https://brainly.com/question/18650233?referrer=searchResults