Respuesta :
Answer:
Solution of the given Quadratic equation are +5√2 and -5√2.
Step-by-step explanation:
We are given Quadratic Equation,
[tex]50-x^2=0[/tex]
To find: Solutions of the given quadratic equation.
Consider,
[tex]50-x^2=0[/tex]
transpose x² to RHS,
[tex]50=x^2[/tex]
Now transpose whole RHS to LHS and whole LHS to RHS,
[tex]x^2=50[/tex]
Now, Apply square root both sides,
[tex]x=\pm\sqrt{50}[/tex]
[tex]x=\pm\sqrt{2\times5\times5}[/tex]
[tex]x=\pm5\sqrt{2}[/tex]
Therefore, Solution of the given Quadratic equation are +5√2 and -5√2.