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Use the counting principle to find the probability of choosing the 8 winning lottery numbers when the numbers are chosen at random from 0-9

Respuesta :

10^8 possible ticket numbers 
Chances of winning: 1/100,000,000 

Answer:

The probability of choosing the 8 winning lottery numbers when the numbers are chosen at random from 0-9 is:

                     [tex]\dfrac{1}{10^8}[/tex]

Step-by-step explanation:

We know that there are total 10 numbers from 0-9

As all of the 8 numbers may repeat.

Hence, total number of ticket number possible are:10×10×10×10×10×10×10×10=10^8

Now the probability of choosing the 8 winning lottery numbers is given by:

      [tex]Probability=\dfrac{1}{10}\times \dfrac{1}{10}\times \dfrac{1}{10}\times \dfrac{1}{10}\times \dfrac{1}{10}\times \dfrac{1}{10}\times \dfrac{1}{10}\times \dfrac{1}{10}=\dfrac{1}{10^8}[/tex]

                   Hence, the answer is:

                  [tex]\dfrac{1}{10^8}[/tex]