Respuesta :
SA=2(LW+LH+WH)
if W turns to 1/7W
and H turns to 1/7H
SA=2(L(1/7)W+L(1/7)H+(1/7)W(1/7)H)
SA=2((1/7)LW+(1/7)LH+(1/49)WH)
SA=2(1/7)(LW+LH+(1/7)WH)
SA=(2/7)(LW+LH+(1/7)WH)
if W turns to 1/7W
and H turns to 1/7H
SA=2(L(1/7)W+L(1/7)H+(1/7)W(1/7)H)
SA=2((1/7)LW+(1/7)LH+(1/49)WH)
SA=2(1/7)(LW+LH+(1/7)WH)
SA=(2/7)(LW+LH+(1/7)WH)
Answer:
SA = [tex]2(\frac{lw}{7}+\frac{lh}{7}+\frac{wh}{49})[/tex]
Step-by-step explanation:
The surface area of a rectangular prism is given by :
[tex]SA=2(wl+hl+hw)[/tex]
Where l stands for length
w stands for width
h stands for height
Given is - If the width and height of a rectangular prism are each shrunk to one seventh of the original size but the length remains the same.
So, length = l
width = [tex]\frac{w}{7}[/tex]
height = [tex]\frac{h}{7}[/tex]
The new surface area will be =
SA = [tex]2(l\times \frac{w}{7} +l\times \frac{h}{7}+ \frac{w}{7}\times \frac{h}{7})[/tex]
Simplifying this we get:
SA = [tex]2(\frac{lw}{7}+\frac{lh}{7}+\frac{wh}{49})[/tex]
There are many other ways to write this but it has the same meaning, so, we can take this as the answer.
SA = [tex]2(\frac{lw}{7}+\frac{lh}{7}+\frac{wh}{49})[/tex]