Respuesta :
2x^2 - 8x - 3 = 0
Divide out the 2
x^2 - 4x - 3/2 = 0
Move constant to the other side
x^2 - 4x = 3/2
Half and square -4 and add to both sides
x^2 - 4x + 4 = 3/2 + 4
Write left side as a square, simplify the right
(x - 2)^2 = 22/4
Take the square root
x - 2 = +/- SQRT(22) / 2
Add 2
x = 2 +/- SQRT(22) / 2
Divide out the 2
x^2 - 4x - 3/2 = 0
Move constant to the other side
x^2 - 4x = 3/2
Half and square -4 and add to both sides
x^2 - 4x + 4 = 3/2 + 4
Write left side as a square, simplify the right
(x - 2)^2 = 22/4
Take the square root
x - 2 = +/- SQRT(22) / 2
Add 2
x = 2 +/- SQRT(22) / 2
I hope this helps you
ax^2+bx+c=0
disctirminant = b^2-4ac
x1,2= -b (+,-) square root of disctirminant/2a
2x^2+8x-3=0
a= 2 b= 8 c= -3
disctirminant =8^2-4.2. (-3)
disctirminant = 64+24
disctirminant = 88
square root of 88= 2 square root of 22
x1= -8+square root of 88/2.2
x1= square root of 22-4/2
x2= -8- square root of 88/2.2
x2= -4- square root of 22/2
ax^2+bx+c=0
disctirminant = b^2-4ac
x1,2= -b (+,-) square root of disctirminant/2a
2x^2+8x-3=0
a= 2 b= 8 c= -3
disctirminant =8^2-4.2. (-3)
disctirminant = 64+24
disctirminant = 88
square root of 88= 2 square root of 22
x1= -8+square root of 88/2.2
x1= square root of 22-4/2
x2= -8- square root of 88/2.2
x2= -4- square root of 22/2