Respuesta :
If one of the impurities in diesel fuel has the formula c2h6s, then the products that will form would be carbon dioxide, water and sulfur dioxide. The balanced chemical reaction would be as follows:
C2H6S(l) + 9/2O2(g) = 2CO2(g) + 3H2O(v) + SO2(g)
Hope this answers the question.
C2H6S(l) + 9/2O2(g) = 2CO2(g) + 3H2O(v) + SO2(g)
Hope this answers the question.
Answer:
[tex]C_2H_6S(l)+5O_2(g)\rightarrow 2CO_2(g)+3H_2O(g)+SO_3(g)[/tex]
Explanation:
Hello,
In this case, complete combustions are chemical reactions transforming compounds into their respective highest-oxidized oxides, it means, that for the given compound, the carbon will have +4 as its oxidation state, forming carbon dioxide as well as sulfur which will have +6, forming sulfur trioxide. Do not forget water is also formed as an "oxide" of hydrogen. Thus, the aforementioned chemical reaction is:
[tex]C_2H_6S+O_2\rightarrow CO_2+H_2O+SO_3[/tex]
Thus, since the impurity will be in same segregation state of the fuel, that is liquid, and oxygen and all the products are gaseous we have:
[tex]C_2H_6S(l)+O_2(g)\rightarrow CO_2(g)+H_2O(g)+SO_3(g)[/tex]
Finally, by balancing it, we then obtain:
[tex]C_2H_6S(l)+5O_2(g)\rightarrow 2CO_2(g)+3H_2O(g)+SO_3(g)[/tex]
Best regards.