Respuesta :
The test contains 10 three-point questions and 14 five-point questions.
let 'x+y=24' be equation 1
and
'3x+5y=100' be equation 2
multiply equation 1 by 3
so 3x+3y=72 (this is equation 3)
then subtract equation 2 from 3
3x+3y=72
- 3x-5y=-100
----------------------
-2y=-28
divide by 2 on both sides
-2y/2 = -28/2
-y = - 14
if -y= -14 then +y=+14
then put y in equation 1(or 2, you have a choice but 1 is easier)
which will be
x+y= 24
x+14=24
minus 14 on both sides
x+14-14= 24-14
so
x=10
y=14 and x= 10 your answer
however on the exam paper you would write it like this :
'x +y =24' ⇒1
'3x+5y=100' ⇒2
x equation 1 by 3
3x+3y=72
subtract equation 2 from 3
3x+3y=72
- 3x-5y=-100
----------------------
-2y=-28
-2y/2 = -28/2
-y = - 14
if -y= -14 then +y=+14
put y in equation 1
x+y= 24
x+14=24
x+14-14= 24-14
x=10
y=14 so 5 point answers and x=10 3 point answers
I know its long but you need to understand this.
Hope it helped :)
and
'3x+5y=100' be equation 2
multiply equation 1 by 3
so 3x+3y=72 (this is equation 3)
then subtract equation 2 from 3
3x+3y=72
- 3x-5y=-100
----------------------
-2y=-28
divide by 2 on both sides
-2y/2 = -28/2
-y = - 14
if -y= -14 then +y=+14
then put y in equation 1(or 2, you have a choice but 1 is easier)
which will be
x+y= 24
x+14=24
minus 14 on both sides
x+14-14= 24-14
so
x=10
y=14 and x= 10 your answer
however on the exam paper you would write it like this :
'x +y =24' ⇒1
'3x+5y=100' ⇒2
x equation 1 by 3
3x+3y=72
subtract equation 2 from 3
3x+3y=72
- 3x-5y=-100
----------------------
-2y=-28
-2y/2 = -28/2
-y = - 14
if -y= -14 then +y=+14
put y in equation 1
x+y= 24
x+14=24
x+14-14= 24-14
x=10
y=14 so 5 point answers and x=10 3 point answers
I know its long but you need to understand this.
Hope it helped :)