Respuesta :
easey
f(x)=ax^2+bx+c
leading coefient is a
f(x)=1x^2-8x-4
leading coefient is 1
f(x)=ax^2+bx+c
leading coefient is a
f(x)=1x^2-8x-4
leading coefient is 1
Answer:
The answer is
the value of the leading coefficient is equal to [tex]1[/tex]
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to
[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]
in this problem we have
[tex]f(x)=x^{2} -8x-4[/tex]
equate the function to zero
[tex]x^{2} -8x-4=0[/tex]
so
[tex]a=1\\b=-8\\c=-4[/tex]
the value of the leading coefficient is equal to a
[tex]a=1[/tex]