Respuesta :
Complete ionic:
Cu(aq) + 2Cl(aq) + 8O(aq) + 2Na(aq) + C(aq) + 3O(aq) = CaCO3(s) + 2Na(aq) + Cl(aq) + 4O(aq)
Net ionic:
Cu(aq) + Cl(aq) + 4O(aq) + 2Na(aq) + C(aq) + 3O(aq) = CaCO3(s)
So write everything out as IF it will dissociate in water. So everything that is aq splits but solid just floats to the bottom of the mixture. Cancel what you can (in this case the two from the ClO4 on the left of the equation cancels with the ClO4 from the right) and the 2Na cancels. Then, write out the whole solution and you are done!
Cu(aq) + 2Cl(aq) + 8O(aq) + 2Na(aq) + C(aq) + 3O(aq) = CaCO3(s) + 2Na(aq) + Cl(aq) + 4O(aq)
Net ionic:
Cu(aq) + Cl(aq) + 4O(aq) + 2Na(aq) + C(aq) + 3O(aq) = CaCO3(s)
So write everything out as IF it will dissociate in water. So everything that is aq splits but solid just floats to the bottom of the mixture. Cancel what you can (in this case the two from the ClO4 on the left of the equation cancels with the ClO4 from the right) and the 2Na cancels. Then, write out the whole solution and you are done!
The net ionic equation of the chemical reaction is:
[tex]Cu^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CuCO_3(s)[/tex]
Given:
[tex]Cu(ClO_4)_2(aq) + Na_2CO_3(aq)\rightarrow CuCO_3(s) + 2NaClO_4(aq)[/tex]
To find:
The net ionic equation of the chemical reaction.
Solution:
- The copper(II) perchlorate dissociates into copper(II) ion and perchlorate ions in their aqueous solution:
⇒ [tex]Cu(ClO_4)_2(aq) \rightarrow Cu^{2+}(aq)+2ClO_4^-(aq)...[1][/tex]
- The sodium carbonate dissociates into a sodium ion and carbonate ions in their aqueous solution:
⇒ [tex]Na_2CO_3(aq) \rightarrow 2Na^{+}(aq)+CO_3^{2-}(aq)...[2][/tex]
- The sodium perchlorate dissociated into a sodium ion and perchlorate ions in their aqueous solution:
⇒ [tex]NaClO_4(aq) \rightarrow Na^{+}(aq)+ClO_4^-(aq)...[3][/tex]
Using equation [1] , [2], and [3] given chemical reaction:
[tex]Cu^{2+}(aq)+2ClO_4^-(aq)+2Na^{+}(aq)+CO_3^{2-}(aq)\rightarrow \\[/tex]
[tex]CuCO_3(s) +2Na^{+}(aq)+2ClO_4^-(aq)[/tex]
For the net ionic equation remove common ions from both sides of the equation:
[tex]Cu^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CuCO_3(s)[/tex]
The net ionic equation of the chemical reaction is:
[tex]Cu^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CuCO_3(s)[/tex]
Learn more about the net ionic equation here:
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