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How many moles of Ca3N2 will be produced if you react 6.3 moles of Calcium with an excess (more than you need) of Nitrogen?
3Ca + N2→ Ca3N2

a) 18.9 moles of Ca3N2
b) 6.3 moles of Ca3N2
c) 2.1 moles of Ca3N2

Respuesta :

Answer:

C

Explanation:

For every mol of Ca3N2 produced, you will need 3 mols of Ca

So the answer can be set up using a proportion.

3/1 = 6.3 / x               Cross multiply

3x = 6.3 *1                 Divide by 3

3x/3 = 6.3/3

x = 2.1

The answer is C

2.1 moles of Ca3N2 will be produced if you react 6.3 moles of Calcium with an excess nitrogen. Details about stoichiometry can he be found below.

How to calculate number of moles?

The number of moles of a compound can be calculated as follows:

The chemical reaction between calcium and nitrogen is given as follows:

3Ca + N2→ Ca3N2

Based on the above reaction, 3 moles of calcium forms 1 mole of Ca3N2

Hence, 6.3 moles of calcium will produce 6.3/3

= 2.1 moles of Ca3N2

Therefore, 2.1 moles of Ca3N2 will be produced if you react 6.3 moles of calcium with an excess nitrogen.

Learn more about stoichiometry at: https://brainly.com/question/9743981

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