Answer:
[tex]\boxed {\boxed {\sf D. \ 64 \ grams }}[/tex]
Explanation:
Given the moles, we are asked to find the mass of a sample.
We know that the molar mass of methanol is 32.0 grams per mole. We can use this number as a fraction or ratio.
[tex]\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}[/tex]
Multiply by the given number of moles, which is 2.0
[tex]2.0 \ mol \ CH_3OH *\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}[/tex]
The moles of methanol will cancel each other out.
[tex]2.0 \ *\frac{32 \ g \ CH_3OH}{1 }[/tex]
The denominator of 1 can be ignored.
[tex]2.0 * 32 \ g\ CH_3OH[/tex]
Multiply.
[tex]64 \ g \ CH_3OH[/tex]
There are 64 grams of methanol in the sample.
