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1. Calculate the mass of the product, if you started with 4 g of Zn and 3 g of H2CO3.
Zn + H2CO3
ZnCO2 + H2 * I’ll cash app for the right answer plus explanation”

1 Calculate the mass of the product if you started with 4 g of Zn and 3 g of H2CO3 Zn H2CO3 ZnCO2 H2 Ill cash app for the right answer plus explanation class=

Respuesta :

sebassandin

Answer:

6.07 g.

Explanation:

Hello!

In this case, given the chemical reaction:

[tex]Zn + H_2CO_3 \rightarrow ZnCO_3 + H_2[/tex]

We first need to compute the moles of each reactant considering their molar masses:

[tex]n_{Zn}=4gZn*\frac{1molZn}{65.38 gZn} =0.0612molZn\\\\n_{H_2CO_3}=3gH_2CO_3*\frac{1molH_2CO_3}{62.03 gH_2CO_3} =0.0484molH_2CO_3[/tex]

Now, compute the mass of zinc carbonate yielded by each reactant in order to pick out the correct limiting reactant:

[tex]n_{ZnCO3}^{by\ Zn} = 0.0612molZn*\frac{1molZnCO3}{1molZn}*\frac{125.4 gZnCO3}{1molZnCO3}=7.67gZnCO3 \\\\n_{ZnCO3}^{by\ H_2CO3} = 0.0484molH_2CO3*\frac{1molZnCO3}{1molH_2CO3}*\frac{125.4 gZnCO3}{1molZnCO3}=6.07gZnCO3[/tex]

Thus, we conclude carbonic acid is the limiting reactant as it produces the fewest grams of product and therefore the yielded mass of zinc carbonate product 6.07 g.

Best regards.

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