Answer:
[tex]f(3) = 38[/tex]
Step-by-step explanation:
Given the quadratic function
[tex]f\left(x\right)=\:5x^2\:-\:4x\:+\:9[/tex]
Evaluating the quadratic function
[tex]f\left(x\right)=\:5x^2\:-\:4x\:+\:9[/tex]
substitute x = 3
[tex]f\left(3\right)=\:5\left(3\right)^2\:-\:4\left(4\right)\:+\:9[/tex]
[tex]f(3) = 45-16+9[/tex]
[tex]f(3) = 38[/tex]
Therefore,