Answer:
[tex](a):\ y = \frac{x + 3}{7}[/tex] --- Function
[tex](b):[/tex] Not a function
[tex](c):[/tex] A function
Step-by-step explanation:
Given
See attachment
Required
Determine if each relation is a relation or not
A function is represented as: [tex]\{(x_1,y_1),(x_2,y_2),(x_3,y_3)...(x_n,y_n)\}[/tex]
Where
[tex]x = domain[/tex] and [tex]y = range[/tex]
For a relation to be a function:
No x value (in other words, the domain) must be repeated
[tex](a):\ y = \frac{x + 3}{7}[/tex]
The above relation is a function. This is so because every unique value of x have a unique value of y.
In other words:
No two domains exist for a range
Conclusively, it is a one-to-one function
[tex](b):[/tex]
[tex]\begin{array}{ccccc}x & {-2} & {-2} & {1} & {3} \ \\ y & {-5} & {-1} & {3} & {7} \ \ \end{array}[/tex]
In the above table, we have:
[tex](x_1,y_1) = (-2,5)[/tex] and [tex](x_2,y_2) = (-2,-1)[/tex]
The domain (-2) points to range (5 and -1).
Based on the condition that no two domain should point to the same range, we can conclude that this is not a function.
[tex](c):[/tex]
[tex]\begin{array}{ccccc}x & {-3} & {-1} & {1} & {3} \ \\ y & {-4} & {-4} & {2} & {2} \ \ \end{array}[/tex]
In the above table, we have the domain to be:
[tex]x = \{-3,-1,1,3\}[/tex]
We can see that no x value is repeated.
Hence, this is a function.
