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Consider an open pipe of length L. What are the wavelengths of the three lowest tones produced by this pipe? Consider an open pipe of length L. What are the wavelengths of the three lowest tones produced by this pipe?

A. 3L, L, L/3

B. 2L, L, L/2

C. 2L, L, L/2

D. 4L, 2L, L 2L, L, 2L/3

Respuesta :

Answer:

Explanation:

open pipe :

In open pipe , wavelength of tone produced =  2L / n where n is integer .

3 lowest tone or highest wavelength  = 2L / 1 , 2L / 2 , 2L / 3

= 2L , L , 2L/3

Closed pipe :

In closed pipe , wavelength of tone produced =  4L / n where n is odd integer

3 lowest tone or highest wavelength  = 4L / 1 , 4L / 3 , 4L / 5

= 4L  , 4L / 3 , 4L / 5

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