Answer:
[tex]P_x=0.7407407407 \approx 0.74[/tex]
Step-by-step explanation:
From the question we are told that
Dice rolls n=200
Number of dice =2
Generally sample space for Two 6-sided dice is [tex]n=36[/tex]
The sums of five bears the following events
[tex]E={(1,4)(2,3)(3,2)(4,1)}=>4[/tex]
Probability of getting a sum of 5 in a roll
[tex]P(sum 5)=\frac{4}{36}[/tex]
Generally the probability that two dice rowed will include 30 sums of 5
[tex]P_x=\frac{4(200)}{36(30)}[/tex]
[tex]P_x=0.7407407407 \approx 0.74[/tex]
The probability of getting more than 30 sums of 5 out of 200 rolls is 1/6.
Probability is the measurement of possibilities.
Number of rolls =200
Number of dice =2
Sample space for a sum of 5 will be (1,4) (2,3), (3,2),(4,1)
Total outcomes = 36
So, the probability of getting 5 as a sum in a single roll= 4/36 =1/9
So, the probability of getting more than 30 sums of 5 out of 200 rolls
= 1/9 *30/200
=1/6
Hence, the probability of getting more than 30 sums of 5 out of 200 rolls is 1/6.
To get more about probability visit:
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