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A plane rises from take-off and flies at an angle of 8° with the horizontal runway. When it has gained 850 feet, find the distance to the nearest foot, the plane has flown.

850 ft

The plane has flown approximately ___ feet. (Round to the nearest foot.)

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okpalawalter8

Answer:

[tex]C\approx 5748.2feet[/tex]

Step-by-step explanation:

From the question we are told that

Angle of elevation [tex]\thata=8 \textdegree[/tex]

Height of plane [tex]H=850feet[/tex]

Generally the equation for the Distance flown is given by

   [tex]C=\frac{H}{sin \theta}[/tex]

   [tex]C=\frac{800}{sin8}[/tex]

   [tex]C=5748.237227[/tex]

   [tex]C\approx 5748.2feet[/tex]

Therefore Distance flown is

   [tex]C\approx 5748.2feet[/tex]

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