Answer:
[tex]x=(59cos 45\textdegree)t,y=4+(v_0sin45\textdegree)t-16t^2[/tex]
Step-by-step explanation:
From the question we are told that
Height [tex]h=4feet[/tex]
Initial velocity of[tex]v_0=59 feet/sec[/tex]
Angle [tex]\theta= 40\textdegree[/tex]
Generally the parametric equation for projectile motion is mathematically given by
[tex]x=(v_0cos\theta)t,y=y_0+(v_0sin\theta)t-16t^2[/tex]
Therefore
[tex]x=(59cos 45\textdegree)t,y=4+(v_0sin45\textdegree)t-16t^2[/tex]
The parametric equation that represents the path of the football
[tex]x=(59cos 45\textdegree)t,y=4+(v_0sin45\textdegree)t-16t^2[/tex]
