Answer:
the temperature of gas inside the container is 195.2 K.
Explanation:
Given;
volume of gas in the container, V = 3.45 L
pressure of gas in the container, P = 2.14 atm
number of gas moles, n = 0.461 mol
The temperature of gas inside the container is calculated as;
[tex]PV = nRT\\\\T = \frac{PV}{nR}[/tex]
where;
R is gas constant = 0.08205 L.atm/mol.K
[tex]T = \frac{2.14 \ \times \ 3.45}{0.461 \ \times \ 0.08205} \\\\T = 195.2 \ K[/tex]
Therefore, the temperature of gas inside the container is 195.2 K.
