A 1.25 m long string attached to a 60.0 Hz vibra

tor created a standing wave with 5 loops. What was the velocity of the waves in the string?


Unit= m/s

Respuesta :

Answer:

The  velocity of the waves in the string is 30 m/s.

Explanation:

Given;

frequency of the wave, F = 60.0 Hz

number of loops, n = 5

length of the string, L = 1.25 m

1 loop, L  = λ/2

For 5 loops;

[tex]L = \frac{5\lambda}{2}[/tex]

where;

λ is the wavelength

[tex]L = \frac{5 \lambda}{2} \\\\5 \lambda = 2L\\\\\lambda = \frac{2L}{5} \\\\\lambda = \frac{2 \ \times \ 1.25}{5} \\\\\lambda = 0.5 \ m[/tex]

The velocity of the waves in the string is calculated as;

V = Fλ

V = (60)(0.5)

V = 30 m/s

Therefore, the  velocity of the waves in the string is 30 m/s.