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Two cars collide and then stick together in an accident.
Car A has a mass of 1000. kg and is moving 5.00 m/s east, and
car B has a mass of 2000. kg and is moving 2.00 m/s west.
What is the speed of the cars after the collision?
b. 1.53m/s
c. 2.43m/s
a. 0.33m/s
d. 3.93m/s

What’s the answer

Two cars collide and then stick together in an accident Car A has a mass of 1000 kg and is moving 500 ms east and car B has a mass of 2000 kg and is moving 200 class=

Respuesta :

Answer:

Option A. 0.33 m/s

Explanation:

From the question given above, the following data were obtained:

Mass of A (mₐ) = 1000 kg

Velocity of A (uₐ) = 5 m/s

Mass of B (m₆) = 2000 kg

Velocity of B (u₆) = 2 m/s

Velocity (v) after collision =?

mₐuₐ – m₆u₆ = v (mₐ + m₆)

(1000 × 5) – (2000 × 2) = v (1000 + 2000)

5000 – 4000 = 3000v

1000 = 3000v

Divide both side by 3000

v = 1000 / 3000

v = 0.33 m/s

Thus, the speed of the cars after collision is 0.33 m/s

The speed of the cars after the collision is 0.33 m/s.

The right option is a. 0.33 m/s

To calculate the speed of the cars after the collision, we use the formula below.

Formula:

  • mu+m'u' = V(m+m')............... Equation 1

Where:

  • m = mass of car A
  • m' = mass of car B
  • u = initial velocity of car A
  • u' = initial velocity of car B
  • V = Speed of the cars after the collision.

make V the subject of the equation

  • V = (mu+m'u')/(m+m').............. Equation 2

From the question,

Given:

  • m = 1000 kg
  • m' = 2000 kg
  • u = 5 m/s east
  • u' = -2 m/s west

Substitute these values into equation 2

  • V = [(1000×5)+(2000×(-2))]/(1000+2000)
  • V = (5000-4000)/(3000)
  • V = 1000/3000
  • V = 0.33 m/s

Hence, The speed of the cars after the collision is 0.33 m/s.

The right option is a. 0.33 m/s

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