Respuesta :
Answer:
A
Step-by-step explanation:
Given :
2x + 4y = 14 ---------- eq 1
4x + y = 20 ---------- eq 2
if you multiply eq 2 by -4 on both sides, you get
-4 (4x + y = 20) = -4 (20)
-16x -4y = -80 --------- eq3
we can see that eq. 1 and eq 2 together forms the system of equations presented in option A, Hence A is equvalent to the orginal system of equations given in the question.
The system of equations which is equivalent to the [tex]2x + 4y = 14[/tex],[tex]4x + y = 20[/tex] is given in option [tex](A)[/tex] i.e. [tex]2x + 4y = 14[/tex] and [tex]-16x - 4y = -80[/tex].
What is system of equations?
System of equations comprises of two or more equations and seeks common solutions to the equations.
We have,
[tex]2x + 4y = 14[/tex] [tex]........(i)[/tex]
[tex]4x + y = 20[/tex] [tex]........(ii)[/tex]
Now,
To check that which option suits best for system of equation,
Lets multiply equation [tex](ii)[/tex] by [tex](-4)[/tex],
[tex](-4) (4x + y) = (-4)*(20)[/tex]
[tex]-16x-4y=-80[/tex],
So, this above obtained equation is in option [tex](A)[/tex].
Hence, we can say that the system of equations which is equivalent to the [tex]2x + 4y = 14[/tex] ,[tex]4x + y = 20[/tex] is given in option [tex](A)[/tex] i.e. [tex]2x + 4y = 14[/tex] and [tex]-16x - 4y = -80[/tex].
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