Name:
Unit 7: Polygons & Quadrilaterals
Homework 5: Rhombi and Squares
Per:
Date:
(2.5
CD =
This is a 2-page document!
Directions: If each quadrilateral below is a rhombus, find the missing measures.
1. UV = 8 and WX = 5
무 7
2. BC = 28 and BD = 32
TU =
T
WU =_10
TX =
B
(284
FD=_16
EF=_16
EC= _32
8
TV =
112
E
V
28
D
28+32²=c?
784+1024=
1,808=1
U2,5
NK =
K
2
NL =_10
3. MK = 24, JL = 20, and mZMJL = 50°
12 ²+10²=c2
244=c²
20
15.GC
mZKNL =
mZKJL =
mZMLK =
ML =
w
JM = _15.6
mZJKM =
mZJML =
M
L
4. Find PQ.
5. Find mZHGI.
N
P
F
(7x-1)
5x + 16
S
(4x + 3) +
J
R
9x - 32
e
1
H
6. Find mZADB.
7. If mZXYZ = 136°, solve for x.
B
W
X
D
(9x + 4)
(13x - 16)° C
R
Z
(10x-8)
Y
Gina Wilson All Things Alan

Question

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Respuesta :

Leslie134525 Leslie134525 · Answer 1 · 2021-01-27T00:12:58+01:00

Answer:

Step-by-step explanation:

1.

Tu=8

WU=10

Tx=5.65

Tv=11.3

Answer Link

ashishdwivedilVT ashishdwivedilVT · Answer 2 · 2022-04-07T14:10:36+02:00

1)TX=XV=√39

2)WX=XU=5

In the given rhombus TUVW

TW=8(Given)

WX=5(Given)

A rhombus is a quadrilateral whose four sides all have the same length.

As we know that diagonals of the rhombus intersect at a right angle

So, by Pythagoras' theorem

[tex]TW^2 = TX^2 + WX^2\\8^2=TX^2 + 5^2\\TX = \sqrt{39}[/tex]

We know that the diagonals of a rhombus bisect each other

So XV =√39

Similarly, XU=WX =5.

Therefore, in the given rhombus TUVW

1)TX=XV=√39

2)WX=XU=5

To get more about rhombus visit:

https://brainly.com/question/20627264