Given :
Density of the water, [tex]\rho = 1000\ kg/m^3[/tex].
Depth of lake, d = 5 m.
To Find :
The pressure at the bottom of the lake due to the depth of water.
Solution :
We know, hydrostatic pressure is given by :
[tex]P = \rho gd[/tex] ( Here, g is acceleration due to gravity, g = 10 m/s².
Putting all values in above equation, we get :
[tex]P = 1000\ kg/m^3 \times 10 \ m/s^2 \times 5\ m\\\\P = 5\times 10^4 \ Pascal[/tex]
Hence, this is the required solution.
